# What is the Magnitude of Acceleration in Physics? | Try this Calculator

The rate at which velocity varies is called acceleration. Acceleration is a vector quantity since velocity is a vector quantity. As a result, it necessitates both magnitude and direction.

## Calculating Magnitude — Try this formula

To calculate magnitude, we use formulas and relations. Units can be used to represent magnitude. For example, the SI unit for acceleration is ms2, defined as a change in velocity over time. Various factors influence acceleration, including velocity, time, force, etc.

Acceleration is measured in units of times squared per second (ms2). This means that acceleration is a vector quantity and needs to be in the form of a velocity multiplied by time. For example, if a car travels at speed v for 2 seconds, then its acceleration would be as follows:

*ms [= m/s2] vs [= s/2] = v × t = (v × 2) / t = (v × 4) / t = 20 ms2*

When calculating the magnitude of acceleration, you have to know the units on both sides. Be careful about this since the formula and relations can be misleading.

For example, if you know that an object is going at a constant speed of 20 ms2 for 2 seconds, you’d think it’s going 20 m/s2 for 2 seconds. However, in real life, v and t are measured in meters per second and seconds, respectively. So the actual magnitude of the acceleration is 2 meters/s2 for 2 seconds.

## The magnitude of Acceleration and Relation of Velocity

In general, the magnitude of the acceleration is a scalar quantity. This means it has a magnitude but also a direction. Then, if both are known, you can calculate how the change occurred.

For example, if you know that an object changes from 20 ms2 to 2 ms2 for 2 seconds, then this is represented as (v × t) = (20 ms2 × 2 s) = 40 ms2

Therefore, since both v and t are scalars, this quantity can represent the magnitude and direction of acceleration. In practice, the magnitude is used to represent the magnitude of acceleration. To calculate the direction, you need to know the change in velocity and time.

A more sophisticated version using differentiation:

Since velocity and time are always measured in one dimension (length), acceleration is a scalar. If you wanted to represent it as a vector, you would have to do it differently:

This is also convenient for calculating acceleration when speed, time, and distance are known:

The car accelerates from 20 ms2 to 40 ms2 in 2 seconds in the above example. The change in distance is 10 m over 2 s. This corresponds to 40/20 = 1.67 m/s or 167 km/h = 125 mph or 88 m/s.

On a more fundamental level, if you were driving in a car accelerating from 20 ms2 to 40 ms2, the car would quickly move faster. However, if you do not know how fast you are moving, this would not be very clear. So if you know the distance and time, acceleration is used to calculate speed and vice versa:

Since acceleration is a vector, it always has a positive or negative sign associated with it, depending on how it changes the velocity. Suppose you reverse the direction of the acceleration (the direction in which the velocity is changing). In that case, you are also reversing the sign.

The above example showed a negative acceleration because v decreased from 20 m/s to 0 when t increased from 0 to 2 s.

## Proportionality of Acceleration to Velocity

When acceleration increases, then velocity decreases. If they are negative, then this decreases velocity. If they are positive, then this increases velocity.

The opposite of acceleration is deceleration. This is because velocity and time are both positive quantities in this case, and “deceleration” means that they decrease concerning each other.

Note that if you reverse the direction of deceleration, you reverse the sign of both v and t. Thus, unlike acceleration, negative signs only occur when an adverse change in velocity or time occurs.

## Newton Relation of F=ma

The Converse of Newton’s Second Law states that: “*Force is proportional to acceleration only if the mass is constant.”* So as acceleration increases, the force also increases correspondingly by a factor equal to mass divided by acceleration, following Newton’s second law.

If you want to measure the force of an object on another object, you have to measure the acceleration, which would give you the force and not just the force.

This is because the acceleration is proportional to velocity. We used it as a postulate in order for Newton’s first law to work. So if we used it again in this experiment, then it would be wrong because of this very fact.

*F=ma* in Physics

This is a parallel problem which is also a single variable problem with respect to velocity, but instead, there are three variables: position, speed, and time. Therefore, the two problems cannot be swapped out for each other.

This shows that acceleration can vary depending on the situation or condition because the actual force must be measured to be correct. Velocity and time are both measured, meaning they are both perpendicular lines, meaning they do not affect each other. Newton’s second law only applies to constant velocity problems, not variable ones. This means that there is no question for Newton’s second law since it has nothing to do with the problem at hand.